Wednesday, February 6, 2008

Perfection : Problem No. 382

Submitted solution with Run Time = 0.010

#include<iostream>
#include<vector>

using namespace std;

int main()
{
vector<int> nos;
int t,sum,i;

cin>>t;
while(t!=0)
{
nos.push_back(t);
cin>>t;
}
nos.push_back(0);
t=0;
sum=1;
cout<<"PERFECTION OUTPUT"<<endl;
while(nos[t]!=0)
{
if(nos[t] == 1)
{
cout<<" "<<nos[t]<<" ";
// printf("%5d ",nos[t]);
cout<<"DEFICIENT"<<endl;
t++;
}
else
{
for(i=2;i<nos[t];i++)
{
if(nos[t]%i==0)
{
sum=sum+i;
}
}

if(nos[t]/10==0)
cout<<" "<<nos[t]<<" ";
else if(nos[t]/100==0)
cout<<" "<<nos[t]<<" ";
else if(nos[t]/1000==0)
cout<<" "<<nos[t]<<" ";
else if(nos[t]/10000==0)
cout<<" "<<nos[t]<<" ";
else if(nos[t]/100000==0)
cout<<nos[t]<<" ";

// printf("%5d ",nos[t]);
if(sum==nos[t])
{
cout<<"PERFECT"<<endl;
}
else if(sum>nos[t])
{
cout<<"ABUNDANT"<<endl;
}
else if(sum<nos[t])
{
cout<<"DEFICIENT"<<endl;
}
sum=1;
t++;
}
}

cout<<"END OF OUTPUT"<<endl;
//system("pause");
return 0;
}

Comment for better algorithm.

Ecological Bin Packing : Problem No. 102

Submitted solution with Run Time = 0.310


#include<iostream>
#include<string>
#include<vector>
#include<cmath>

using namespace std;

int main()
{
int i,x[9],mini,t;
int mov[6];
vector<string> data;
while(cin>>t)
{
x[0]=t;
for(i=1;i<9;i++)
{
cin>>x[i];
}
// original is bgc
//bcg
mov[0]=x[3]+x[6]+x[2]+x[8]+x[1]+x[4];
data.push_back("BCG");
//bgc
mov[1]=x[3]+x[6]+x[1]+x[7]+x[2]+x[5];
data.push_back("BGC");
//cbg
mov[2]=x[5]+x[8]+x[0]+x[6]+x[1]+x[4];
data.push_back("CBG");
//cgb
mov[3]=x[8]+x[5]+x[1]+x[7]+x[0]+x[3];
data.push_back("CGB");
//gbc
mov[4]=x[4]+x[7]+x[0]+x[6]+x[2]+x[5];
data.push_back("GBC");
//gcb
mov[5]=x[4]+x[7]+x[2]+x[8]+x[0]+x[3];
data.push_back("GCB");

mini=mov[0];

for(i=0;i<6;i++)
mini=min(mini,mov[i]);

for(i=0;i<6;i++)
{
if(mov[i]==mini)
{
cout<<data[i]<<" "<<mov[i]<<endl;
break;
}
}
}

return 0;

}

Comment for better algorithm.

Hashmat the Brave Warrior : Problem No. 10055

Solution submitted with Run Time = 1.210

#include<iostream>
#include<cmath>

using namespace std;

int main()
{
long long m,n;

while(cin>>m>>n)
{
if((m-n)>0)
cout<<m-n<<endl;
else
cout<<n-m<<endl;
}

return 0;
}

Comment for better algorithm.

Tuesday, February 5, 2008

Train Swapping : Problem No. 299

Submitted solution with Rum Time = 0.010

#include<iostream>
#include<vector>

using namespace std;

int main()
{
int count=0,n,t,i,j,k,m;
vector<int> car;

cin>>n;

for(i=0;i<n;i++)
{
cin>>t;
if(t==1)
{cin>>j;
cout<<"Optimal train swapping takes 0 swaps."<<endl;
}
else
{
car.resize(t);
for(j=0;j<t;j++)
{
cin>>car[j];
}
for(j=0;j<t;j++)
{
for(k=0;k<t-j-1;k++)
{
if(car[k+1]<car[k])
{
m=car[k+1];
car[k+1]=car[k];
car[k]=m;
count++;
}
}
}
cout<<"Optimal train swapping takes "<<count<<" swaps."<<endl;
count=0;
}
}
return 0;
}

Comment for better algorithm or lesser run time.

Kindergarten Counting Game : Problem No. 494

Submitted solution with Run Time = 0.000

#include<iostream>
#include<string>

using namespace std;

int main()
{
string str;
int i,count;

while(getline(cin,str))
{
i=0;
count=0;

while(str[i]!='\0')
{
if((str[i]>=65 && str[i]<=90) || (str[i]>=97 && str[i]<=122))
{
count++;
while((str[i]>=65 && str[i]<=90) || (str[i]>=97 && str[i]<=122))
{
i++;
}
}
i++;
}
cout<<count<<endl;
}

return 0;
}


Comment for better algorithm.

Sunday, February 3, 2008

The Decoder : Problem No. 458

Submitted solution with Run Time = 0.330

#include<iostream>
#include<string>

using namespace std;

int main()
{
string str,nstr;
int i;

while(getline(cin,str))
{
i=0;
nstr.resize(str.size());
while(str[i])
{
nstr[i]=str[i]-7;
i++;
}
cout<<nstr<<endl;
}
return(0);
}

Do comment for better solution or any query.

Saturday, February 2, 2008

Tex Quotes : Problem No. 272

My submitted solution :-

#include<iostream>
#include<string>

using namespace std;

int main()
{
string str;

int i,j,t=0;
while(getline(cin,str))
{
for(i=0;i<str.length();i++)
{
if(str[i]=='"' && (t+1)%2==1)
{
str=str+str[str.length()-1];
for(j=str.length();j>i;j--)
{
str[j]=str[j-1];
}
str[i]=str[i+1]='`';
t++;
}
else if(str[i]=='"' && (t+1)%2==0)
{
str=str+str[str.length()-1];
for(j=str.length();j>i;j--)
{
str[j]=str[j-1];
}
str[i]=str[i+1]='\'';
t++;
}
}
cout<<str<<endl;
}

return 0;
}

Comment for better algorithm or any query you have.
Run Time = 0.020